Arc length worksheet

For y = f(x) the length is the integral of √(1 + f′(x)²). For a parametric curve it is the integral of √(x′(t)² + y′(t)²), which is the speed added up over time.

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Pick more than one for a sheet that mixes them.



Sigma Prep · sigmaprep.io/worksheets Name Arc Length Date Period Find the length of each curve. Give exact values. Find the length of $y = \frac{x^{4}}{8} + \frac{1}{4 x^{2}}$ from $x = 1$ to $x = 2$ Find the length of $x = 6 \cos t$ , $y = 6 \sin t$ for $0 \leq t \leq \frac{π}{6}$ Find the length of $x = \frac{t^{2}}{2}$ , $y = \frac{t^{3}}{3}$ for $0 \leq t \leq \sqrt{8}$ Find the length of $y = \frac{x^{4}}{8} + \frac{1}{4 x^{2}}$ from $x = 1$ to $x = 3$ Find the length of $y = x^{\frac{3}{2}}$ from $x = 0$ to $x = \frac{32}{9}$ Find the length of $y = \frac{1}{3} {(x^{2} + 2)}^{\frac{3}{2}}$ from $x = 0$ to $x = 1$ Find the length of $y = \frac{1}{3} {(x^{2} + 2)}^{\frac{3}{2}}$ from $x = 0$ to $x = 2$ Find the length of $y = \frac{x^{3}}{6} + \frac{1}{2 x}$ from $x = 1$ to $x = 3$ Find the length of $y = \frac{2}{3} x^{\frac{3}{2}}$ from $x = 0$ to $x = 8$ Find the length of $y = \frac{x^{2}}{4} - \frac{\ln x}{2}$ from $x = 1$ to $x = 3$ Find the length of $y = \frac{x^{3}}{6} + \frac{1}{2 x}$ from $x = 1$ to $x = 2$ Find the length of $y = \frac{1}{3} {(x^{2} + 2)}^{\frac{3}{2}}$ from $x = 0$ to $x = 4$ Find the length of $x = 5 \cos t$ , $y = 5 \sin t$ for $0 \leq t \leq \frac{π}{2}$ Find the length of $y = \frac{x^{2}}{4} - \frac{\ln x}{2}$ from $x = 1$ to $x = 7$ Find the length of $y = \frac{x^{3}}{6} + \frac{1}{2 x}$ from $x = 1$ to $x = 4$ Find the length of $x = 2 \cos t$ , $y = 2 \sin t$ for $0 \leq t \leq \frac{π}{3}$ Find the length of $y = x^{\frac{3}{2}}$ from $x = 0$ to $x = \frac{20}{3}$ Find the length of $y = \frac{x^{4}}{8} + \frac{1}{4 x^{2}}$ from $x = 1$ to $x = 4$ Find the length of $y = x^{\frac{3}{2}}$ from $x = 0$ to $x = \frac{4}{3}$ Find the length of $y = \frac{2}{3} x^{\frac{3}{2}}$ from $x = 0$ to $x = 15$ Free math worksheets at sigmaprep.io/worksheets© 2026 Sigma Prep

Sigma Prep · sigmaprep.io/worksheets

Name

Arc Length

Date Period

Find the length of each curve. Give exact values.

Find the length of $y = \frac{x^{4}}{8} + \frac{1}{4 x^{2}}$ from $x = 1$ to $x = 2$
Find the length of $x = 6 \cos t$ , $y = 6 \sin t$ for $0 \leq t \leq \frac{π}{6}$
Find the length of $x = \frac{t^{2}}{2}$ , $y = \frac{t^{3}}{3}$ for $0 \leq t \leq \sqrt{8}$
Find the length of $y = \frac{x^{4}}{8} + \frac{1}{4 x^{2}}$ from $x = 1$ to $x = 3$
Find the length of $y = x^{\frac{3}{2}}$ from $x = 0$ to $x = \frac{32}{9}$
Find the length of $y = \frac{1}{3} {(x^{2} + 2)}^{\frac{3}{2}}$ from $x = 0$ to $x = 1$
Find the length of $y = \frac{1}{3} {(x^{2} + 2)}^{\frac{3}{2}}$ from $x = 0$ to $x = 2$
Find the length of $y = \frac{x^{3}}{6} + \frac{1}{2 x}$ from $x = 1$ to $x = 3$
Find the length of $y = \frac{2}{3} x^{\frac{3}{2}}$ from $x = 0$ to $x = 8$
Find the length of $y = \frac{x^{2}}{4} - \frac{\ln x}{2}$ from $x = 1$ to $x = 3$
Find the length of $y = \frac{x^{3}}{6} + \frac{1}{2 x}$ from $x = 1$ to $x = 2$
Find the length of $y = \frac{1}{3} {(x^{2} + 2)}^{\frac{3}{2}}$ from $x = 0$ to $x = 4$
Find the length of $x = 5 \cos t$ , $y = 5 \sin t$ for $0 \leq t \leq \frac{π}{2}$
Find the length of $y = \frac{x^{2}}{4} - \frac{\ln x}{2}$ from $x = 1$ to $x = 7$
Find the length of $y = \frac{x^{3}}{6} + \frac{1}{2 x}$ from $x = 1$ to $x = 4$
Find the length of $x = 2 \cos t$ , $y = 2 \sin t$ for $0 \leq t \leq \frac{π}{3}$
Find the length of $y = x^{\frac{3}{2}}$ from $x = 0$ to $x = \frac{20}{3}$
Find the length of $y = \frac{x^{4}}{8} + \frac{1}{4 x^{2}}$ from $x = 1$ to $x = 4$
Find the length of $y = x^{\frac{3}{2}}$ from $x = 0$ to $x = \frac{4}{3}$
Find the length of $y = \frac{2}{3} x^{\frac{3}{2}}$ from $x = 0$ to $x = 15$



Sigma Prep · sigmaprep.io/worksheets Name Arc LengthAnswer keyVersion 1 Date Period Find the length of each curve. Give exact values. Find the length of $y = \frac{x^{4}}{8} + \frac{1}{4 x^{2}}$ from $x = 1$ to $x = 2$ $\frac{33}{16}$ Find the length of $x = 6 \cos t$ , $y = 6 \sin t$ for $0 \leq t \leq \frac{π}{6}$ $π$ Find the length of $x = \frac{t^{2}}{2}$ , $y = \frac{t^{3}}{3}$ for $0 \leq t \leq \sqrt{8}$ $\frac{26}{3}$ Find the length of $y = \frac{x^{4}}{8} + \frac{1}{4 x^{2}}$ from $x = 1$ to $x = 3$ $\frac{92}{9}$ Find the length of $y = x^{\frac{3}{2}}$ from $x = 0$ to $x = \frac{32}{9}$ $\frac{208}{27}$ Find the length of $y = \frac{1}{3} {(x^{2} + 2)}^{\frac{3}{2}}$ from $x = 0$ to $x = 1$ $\frac{4}{3}$ Find the length of $y = \frac{1}{3} {(x^{2} + 2)}^{\frac{3}{2}}$ from $x = 0$ to $x = 2$ $\frac{14}{3}$ Find the length of $y = \frac{x^{3}}{6} + \frac{1}{2 x}$ from $x = 1$ to $x = 3$ $\frac{14}{3}$ Find the length of $y = \frac{2}{3} x^{\frac{3}{2}}$ from $x = 0$ to $x = 8$ $\frac{52}{3}$ Find the length of $y = \frac{x^{2}}{4} - \frac{\ln x}{2}$ from $x = 1$ to $x = 3$ $2 + \frac{1}{2} \ln 3$ Find the length of $y = \frac{x^{3}}{6} + \frac{1}{2 x}$ from $x = 1$ to $x = 2$ $\frac{17}{12}$ Find the length of $y = \frac{1}{3} {(x^{2} + 2)}^{\frac{3}{2}}$ from $x = 0$ to $x = 4$ $\frac{76}{3}$ Find the length of $x = 5 \cos t$ , $y = 5 \sin t$ for $0 \leq t \leq \frac{π}{2}$ $\frac{5 π}{2}$ Find the length of $y = \frac{x^{2}}{4} - \frac{\ln x}{2}$ from $x = 1$ to $x = 7$ $12 + \frac{1}{2} \ln 7$ Find the length of $y = \frac{x^{3}}{6} + \frac{1}{2 x}$ from $x = 1$ to $x = 4$ $\frac{87}{8}$ Find the length of $x = 2 \cos t$ , $y = 2 \sin t$ for $0 \leq t \leq \frac{π}{3}$ $\frac{2 π}{3}$ Find the length of $y = x^{\frac{3}{2}}$ from $x = 0$ to $x = \frac{20}{3}$ $\frac{56}{3}$ Find the length of $y = \frac{x^{4}}{8} + \frac{1}{4 x^{2}}$ from $x = 1$ to $x = 4$ $\frac{2055}{64}$ Find the length of $y = x^{\frac{3}{2}}$ from $x = 0$ to $x = \frac{4}{3}$ $\frac{56}{27}$ Find the length of $y = \frac{2}{3} x^{\frac{3}{2}}$ from $x = 0$ to $x = 15$ $42$ Free math worksheets at sigmaprep.io/worksheets© 2026 Sigma Prep

Sigma Prep · sigmaprep.io/worksheets

Name

Arc LengthAnswer keyVersion 1

Date Period

Find the length of each curve. Give exact values.

Find the length of $y = \frac{x^{4}}{8} + \frac{1}{4 x^{2}}$ from $x = 1$ to $x = 2$ $\frac{33}{16}$
Find the length of $x = 6 \cos t$ , $y = 6 \sin t$ for $0 \leq t \leq \frac{π}{6}$ $π$
Find the length of $x = \frac{t^{2}}{2}$ , $y = \frac{t^{3}}{3}$ for $0 \leq t \leq \sqrt{8}$ $\frac{26}{3}$
Find the length of $y = \frac{x^{4}}{8} + \frac{1}{4 x^{2}}$ from $x = 1$ to $x = 3$ $\frac{92}{9}$
Find the length of $y = x^{\frac{3}{2}}$ from $x = 0$ to $x = \frac{32}{9}$ $\frac{208}{27}$
Find the length of $y = \frac{1}{3} {(x^{2} + 2)}^{\frac{3}{2}}$ from $x = 0$ to $x = 1$ $\frac{4}{3}$
Find the length of $y = \frac{1}{3} {(x^{2} + 2)}^{\frac{3}{2}}$ from $x = 0$ to $x = 2$ $\frac{14}{3}$
Find the length of $y = \frac{x^{3}}{6} + \frac{1}{2 x}$ from $x = 1$ to $x = 3$ $\frac{14}{3}$
Find the length of $y = \frac{2}{3} x^{\frac{3}{2}}$ from $x = 0$ to $x = 8$ $\frac{52}{3}$
Find the length of $y = \frac{x^{2}}{4} - \frac{\ln x}{2}$ from $x = 1$ to $x = 3$ $2 + \frac{1}{2} \ln 3$
Find the length of $y = \frac{x^{3}}{6} + \frac{1}{2 x}$ from $x = 1$ to $x = 2$ $\frac{17}{12}$
Find the length of $y = \frac{1}{3} {(x^{2} + 2)}^{\frac{3}{2}}$ from $x = 0$ to $x = 4$ $\frac{76}{3}$
Find the length of $x = 5 \cos t$ , $y = 5 \sin t$ for $0 \leq t \leq \frac{π}{2}$ $\frac{5 π}{2}$
Find the length of $y = \frac{x^{2}}{4} - \frac{\ln x}{2}$ from $x = 1$ to $x = 7$ $12 + \frac{1}{2} \ln 7$
Find the length of $y = \frac{x^{3}}{6} + \frac{1}{2 x}$ from $x = 1$ to $x = 4$ $\frac{87}{8}$
Find the length of $x = 2 \cos t$ , $y = 2 \sin t$ for $0 \leq t \leq \frac{π}{3}$ $\frac{2 π}{3}$
Find the length of $y = x^{\frac{3}{2}}$ from $x = 0$ to $x = \frac{20}{3}$ $\frac{56}{3}$
Find the length of $y = \frac{x^{4}}{8} + \frac{1}{4 x^{2}}$ from $x = 1$ to $x = 4$ $\frac{2055}{64}$
Find the length of $y = x^{\frac{3}{2}}$ from $x = 0$ to $x = \frac{4}{3}$ $\frac{56}{27}$
Find the length of $y = \frac{2}{3} x^{\frac{3}{2}}$ from $x = 0$ to $x = 15$ $42$

How to do these

Find the length of $y = \frac{2}{3} x^{\frac{3}{2}}$ from $x = 0$ to $x = 3$

f′(x) = √x, so the integrand is √(1 + x).
The integral is (2/3)(1 + x)^(3/2) from 0 to 3: (2/3)(8 − 1).

The answer is $\frac{14}{3}$ .

Where students go wrong

Forgetting the 1 under the root. Without it the integral measures something else entirely, and the answer is usually smaller than the straight-line distance, which a length cannot be.

Also called length of a curve, arc length formula or parametric arc length.

Questions about these worksheets

Yes. Every arc length sheet is free to print and free to download as a PDF. There is no account to make, no email to hand over and no limit on how many you take.

Yes. The answer key prints on a second page, and you can choose whether it shows each question beside its answer or just the answers in a list.

Yes. Print straight from the page, or download the PDF and print that. The sheet is laid out for paper rather than squeezed off a screen, so there is room to work under each question, and the answer key comes out on its own page.

Calculus is usually taken around 12th grade or a first college course, though schools vary and plenty of students meet it earlier or later. Pick the difficulty rather than the grade: the easy level suits a first lesson on it, the hard level suits review before a test.

Yes, as many as you like. The questions are built fresh each time rather than picked from a fixed set of files, so pressing Generate gives a new sheet. That is what you want for a second class, a retake, or two students sitting next to each other.

That is the closest comparison, and Kuta Software is good software. It is also paid software you install on a computer. These worksheets run in a browser tab for free, with no account and nothing to install. Like Kuta, the arc length questions are generated when you ask for them rather than pulled from a fixed set of files, so two classes never get the same sheet, and the answer key comes with it.

Yes. There are three levels, and you can tick more than one for a sheet that mixes them, in which case the questions come out easiest first. The harder levels are not just larger numbers: they ask for something the easy ones do not.

Forgetting the 1 under the root. Without it the integral measures something else entirely, and the answer is usually smaller than the straight-line distance, which a length cannot be.

Arc length worksheet

Select your difficulty

Arc Length

Arc LengthAnswer keyVersion 1

How to do these

Where students go wrong

Questions about these worksheets

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